Ethylene Glycol (antifreeze) has a density of 1.11 g/cm^3 the volume in liters will be 2.8 liters of 3.12 kg of ethylene glycol.
The density is the amount of substance present in a per centimeter cube and it is the ratio of the volume and the mass of the substance.
Here, the mass is 3.12 kg and the density is 1.11 g/cm^3 so, the volume of the substance will be
volume = mass÷ density.
Substituting the value,
Volume = 3.12 ÷ 1.11 = 2.8 liters
Therefore, the volume in liters will be of 3.12 kg of ethylene glycol if Ethylene Glycol (antifreeze) has a density of 1.11 g/cm^3.
Learn more about density, here;
https://brainly.com/question/15164682
#SPJ1