A sum of K3,000 is borrowed for 2 years at the reducing balance interest rate of 12% p.a. compounded every two-monthly.
(a) Show the full loan repayment schedule for the two years.
(b) Calculate the balance of loan owing at the end of the seventh repayment period.
(c) How much is the interest paid for this loan? (d) If it decides to terminate the loan after the first year,
find the termination payment required.​

Respuesta :

a) The full loan repayment schedule for the two years is as follows:

Loan Repayment Schedule:

Period          PV                   PMT             Interest               FV

1           $3,000.00          $283.68          $60.00          $2,776.32

2           $2,776.32          $283.68          $55.53           $2,548.17

3           $2,548.17           $283.68          $50.96          $2,315.45

4           $2,315.45           $283.68           $46.31         $2,078.08

5          $2,078.08           $283.68           $41.56          $1,835.97

6           $1,835.97           $283.68          $36.72          $1,589.01

Year #1 end

7          $1,589.01           $283.68           $31.78           $1,337.11

8           $1,337.11          $283.68          $26.74           $1,080.17

9           $1,080.17           $283.68          $21.60             $818.10

10            $818.10           $283.68           $16.36           $550.78

11           $550.78           $283.68            $11.02            $278.12

12           $278.12           $283.68            $5.56            $0.00

Year #2 end

b) The balance of the loan at the end of the seventh repayment period is $1,337.11.

c) The total interest paid for this loan is $404.16.

d) If the borrower decides to terminate the loan after the first year, the termination payment should be $1,589.01.

Data and Calculations:

N (# of periods) = 12 months (2 x 6)

I/Y (Interest per year) = 12%

PV (Present Value) = K3000

FV (Future Value) = K0

Results:

PMT every two months = $283.68

Sum of all periodic payments = $3,404.16 ($283.68 x 12)

Total Interest = $404.16

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