Respuesta :
The events are mutually exclusive events, so P(A|B) is 0.
In this question,
If two events are mutually exclusive, there is no chance that both events will occur. Being the intersection an operation whose result is made up of the non-repeated and common events of two or more sets, that is, given two events A and B, their intersection is made up of the elementary events that they have in common, then
⇒ A ∩ B = 0
Now the conditional probability, P(A|B) = [tex]\frac{P(A \cap B )}{P(B)}[/tex]
⇒ [tex]\frac{0}{0.10}[/tex]
⇒ 0.
Hence we can conclude that the events are mutually exclusive events, so P(A|B) is 0.
Learn more about events and conditional probability here
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