The company's profit in the year 2006, to the nearest tenth of a million dollars is 6.9 million dollars
The given parameters are
Initial = $5.6 million
Rate = 7%
The function is represented as:
f(x) = Initial * (1 + Rate)^x
So, we have
f(x) = 5.6 * (1 + 7%)^x
2006 is 3 years from 2003.
So, we have:
f(3) = 5.6 * (1 + 7%)^3
Evaluate
f(3) = 6.9
Hence, the company's profit in the year 2006, to the nearest tenth of a million dollars is 6.9 million dollars
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