A square loop of wire that encloses an area of 0.20 m^2 is in a uniform magnetic field of 0.10 t. What is the flux through the loop if its plane is at an angle of 62 degrees to the field?

Respuesta :

A square loop of wire that encloses an area of 0.20 m² is in a uniform magnetic field of 0.10 t. The flux through the loop if its plane is at an angle of 62 degrees to the field is 1.8 × 10⁻² Wb.

The amount of magnetic field lines passing through a loop of area A which is tilted at angle θ from the field is defined as magnetic flux and is found by the below formula Φm = B A cos ⁡θ.

Given,

Area of the loop, A = 0.20 m² = 20 × 10⁻² m²,

Magnetic field, B = 0.10T,

As we know, Magnetic flux through a loop (Φm),

Φm = BA cos ⁡θ

⇒ Фm = 0.1 × 20 × 10⁻² × cos 62°

⇒ Фm = 2 × 10⁻² × 0.47

Фm = 1.8 × 10⁻² Wb.

To learn more about Magnetic Flux here

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