Respuesta :
None of these reagent could not be used to separate [tex]Br ^{-}[/tex] from [tex]CO_{3} ^{-2}[/tex]when added to an aqueous solution containing both .
So , correct option is B .
[tex]AgNO_{3} (aq)[/tex] could not used to separate [tex]Br ^{-}[/tex] from [tex]CO_{3} ^{-2}[/tex] . Because, both the ions form precipitate with silver nitrate. Hence it is not possible to separate one from other.
[tex]AgNO_{3} (aq) + Br^- (aq)[/tex] → [tex]AgBr (s) + NO_{3} ^- (aq)[/tex]
[tex]2 AgNO_{3} (aq) + CO_{3} ^2- (aq)[/tex] → [tex]Ag_{2} CO_{3} (s) + 2 NO_{3} ^- (aq)[/tex]
In remaining reagent each only carbonate is precipitated leaving bromide ions in the solution state.
Missing part in the question :
The options are missing
- [tex]Ca(NO_{3} )_{2} (aq)[/tex]
- None of these could be used to separate [tex]Br ^{-}[/tex] from [tex]CO_{3} ^{-2}[/tex] .
- [tex]Cu(NO_{3} )_{2} (aq)[/tex]
- [tex]Fe(NO_{3} )_{2} (aq)[/tex]
- [tex]AgNO_{3} (aq)[/tex]
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