Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not. The square root of the quantity 4 x minus 3 end quantity equals 5.

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Sprnt

Answer:

x= 7.

Step-by-step explanation:

1. Write the expression.

[tex]\sqrt{4x-3}=5[/tex]

2. Take the square root of both sides of the equation.

[tex](\sqrt{4x-3})^{2} =5^{2} \\ \\4x-3=25[/tex]

3. Sum 3 to both sides of the equation.

[tex]4x-3+3=25+3\\ \\4x=28[/tex]

4. Divide by 4 on both sides of the equation.

[tex]\frac{4x}{4} =\frac{28}{4} \\ \\x=7[/tex]

5. Express your result.

x= 7.

Answer:

  • x=7

Step-by-step explanation:

At first let's understanding the situation

The square root of the quantity 4 x minus 3 end quantity equals 5.

we have to find the value if x.

Solution:-

[tex]\sqrt{(4x-3)}=5 [/tex]

By squaring on both sides

[tex]{\sqrt{(4x-3)}}^{2}=5^{2}\\\\\\4x-3=25\\\\4x=25+3\\\\4x=28\\\\x=7 [/tex]