Respuesta :
Answer:
x= 7.
Step-by-step explanation:
1. Write the expression.
[tex]\sqrt{4x-3}=5[/tex]
2. Take the square root of both sides of the equation.
[tex](\sqrt{4x-3})^{2} =5^{2} \\ \\4x-3=25[/tex]
3. Sum 3 to both sides of the equation.
[tex]4x-3+3=25+3\\ \\4x=28[/tex]
4. Divide by 4 on both sides of the equation.
[tex]\frac{4x}{4} =\frac{28}{4} \\ \\x=7[/tex]
5. Express your result.
x= 7.
Answer:
- x=7
Step-by-step explanation:
At first let's understanding the situation
The square root of the quantity 4 x minus 3 end quantity equals 5.
we have to find the value if x.
Solution:-
[tex]\sqrt{(4x-3)}=5 [/tex]
By squaring on both sides
[tex]{\sqrt{(4x-3)}}^{2}=5^{2}\\\\\\4x-3=25\\\\4x=25+3\\\\4x=28\\\\x=7 [/tex]