Mass gained by spring is equal to the force/constant K. We can locate the spring constant of the spring from the given statistics for the four kg mass. Then we use x = F/k to find the displacement of a 1.5 kg mass. The work that have to be carried out to stretch spring a distance x from its equilibrium function is W = ½kx2.
When a mass is hung vertically from a spring, the spring stretches. The force on the mass due to the spring is proportional to the quantity the spring is stretched. There is a point at which the spring force and the weight are equal in magnitude but opposite in direction. This point is referred to as the equilibrium position.
If the gadget was once in one dimension and the potential power feature would be y=U(x)=ax2 then we would without problems locate the equilibrium factor of that machine by using F=−∂U∂x then we would discover the roots of F by way of F=0.
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