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Use rectangle ABCD to answer examples 32-36.

33. Solve for x

32. Write the equation that shows the perimeter of the rectangle is 48 inches.

34. Find the area of the rectangle.

35. Based on the figure above, write the equation that shows the area of the rectangle is 72 square
inches.

36. Find the dimensions of the rectangle based on your findings in #35

Use rectangle ABCD to answer examples 3236 33 Solve for x 32 Write the equation that shows the perimeter of the rectangle is 48 inches 34 Find the area of the r class=

Respuesta :

akposevictor

32. 4x + 12 = 48

33. x = 9

34. Area of rectangle = 135 in.²

35. x² + 6x = 72

36. Width of the rectangle = 6 in.

Length of the rectangle = 12 in.

What is the Area and Perimeter of a Rectangle?

Area = (length)(width).

Perimeter = 2(length + width).

32. Length of rectangle = x + 6

Width of rectangle = x

Perimeter = 48 inches

Therefore, the equation that shows the perimeter is 48 inches, is expressed as:

2(x + x + 6) = 48

2(2x + 6) = 48

4x + 12 = 48

33. 4x + 12 = 48

4x = 48 - 12

4x = 36

x = 9

34. Length of rectangle = x + 6 = 9 + 6 = 15 in.

Width of rectangle = x = 9 in.

Area of rectangle = (15)(9)

Area of rectangle = 135 in.²

35. Area of rectangle = 72 in.²

(x)(x + 6) = 72

x² + 6x = 72

36. x² + 6x = 72

x² + 6x - 72 = 0

Factorize the equation

(x - 6)(x + 12) = 0

x = 6; x = -12

Width of the rectangle = 6 in.

Length of the rectangle = x + 6  = 6 + 6 = 12 in.

Learn more about the rectangle on:

https://brainly.com/question/25292087

#SPJ1

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