Based on the time that you departed Seattle and the layovers in Dallas and Portland, you will arrive in Seattle at 6:45 am.
If you leave Seattle at 9:10 pm, you will arrive in Atlanta at 10:25 am .
If the leg from Dallas back to Atlanta is 2/3 of an hour longer then you will arrive at 11:05 am.
The hours you will spend going from Atlanta to Seattle including layover times is:
= 2.75 + 1.5 + 3.5 + 1.75 + 0.75
= 10 hours 15 minutes
The time you will arrive in Seattle is:
= 11:30 pm + 10 hours 15 minutes - 3 hour time difference
= 6:45 am
Your total flight time and layover time is 10 hours 15 minutes. You will therefore arrive in Atlanta at:
= 9:10 pm + 10 hours 15 minutes + 3 hour time difference
= 10:25 am
If the leg back to Atlanta took an additional 2/3 of an hour then you would arrive at:
= 10:25 + 40 minutes
= 11:05 am
Find out more on solving for flight times at https://brainly.com/question/28206496
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