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Adalyn has nine more than twice the number of skittles than Morgan has. If twice the number of skittles that Adalyn has is two more than five times the number of skittles that Morgan has, how many does each girl have?​

Respuesta :

adioabiola

The number of Skittles Adalyn and Morgan has is 41 and 16 respectively.

Algebra

let

  • Number of Skittles Adalyn has = x
  • Number of Skittles Morgan has = y

x = 2y + 9

twice the number of skittles that Adalyn has is two more than five times the number of skittles that Morgan has,

2x = 5y + 2

  • substitute x = 2y + 9 into

2x = 5y + 2

2(2y + 9) = 5y+2

4y + 18 = 5y+2

  • subtract 4y and 2 on both sides

18 - 2 = 5y - 4y

16 = y

or

y = 16 Skittles

Recall,

x = 2y + 9

= 2(16) + 9

= 32 + 9

= 41 Skittles

Learn more about algebra:

https://brainly.com/question/4344214

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