If the patient is given 150 mL/h of IV saline for 1.5 h 1.97 g NaCl she receive.
Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.
It is expressed as:
Molarity (M) = [tex]\frac{\text{Number of moles}}{\text{Volume of solution in liters}}[/tex]
Molarity × Volume of solution = Number of moles
As we know that
Number of moles = [tex]\frac{\text{Given Mass}}{\text{Molar Mass}}[/tex]
So,
Molarity × Volume of solution =  [tex]\frac{\text{Given Mass}}{\text{Molar Mass}}[/tex]
Molarity × Volume of solution × Molar Mass = Mass
Volume = [tex]\frac{150\ mL}{1\ \text{hour}}[/tex]
       = 225 mL
Mass of NaCl = Molarity × Volume of solution × Molar Mass
            = (0.15 mol/L NaCl) × (58.44 g/mol NaCl) × (225 ml × 0.001)
            = 1.97 g NaCl
Thus from the above conclusion we can say that If the patient is given 150 mL/h of IV saline for 1.5 h 1.97 g NaCl she receive.
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