Eighty proof whiskey is 40% ethanol (C₂H₅OH) by volume. A man has 7.0 L of blood and drinks 28 mL of the whiskey, of which 22% of the ethanol goes into his blood.(b) What volume (in mL) of whiskey would raise his blood alcohol level to 8.0x10⁻⁴ g/mL, the level at which a person is considered intoxicated?

Respuesta :

volume (in mL) of whiskey would raise his blood alcohol level to 8.0x10⁻⁴ g/mL is 23×10⁵ml

According to question

      Eighty proof whiskey is 40% ethanol (C₂H₅OH) by volume

Now,

 Let the volume of whiskey be 100ml,then 40ml ethanol is present.

Now,

 whiskey consumed by the person = 28ml

Hence volume of ethanol= 28 ×[tex]\frac{40}{100}[/tex] ml of ethanol

                                          = 11.2 ml of ethanol

Now 22% of the consumed ethanol goes into blood.

 Hence,

  volume of the consumed ethanol going into the blood is = 11.2×[tex]\frac{22}{100}[/tex]

                                                                                               = 2.5ml of ethanol

Now,

   Volume of ethanol required to raise his level by 8×10⁻⁴[tex]\frac{g}{ml}[/tex] is

 volume = 46.06/ 8×10⁻⁴ ml of ethanol

Hence,

  volume of ethanol = 5.75 × 10⁴ml

Now,

  2.5 ml of ethanol consumed by blood have whiskey= 100ml

Hence,

5.75 × 10⁴ml of ethanol consumed by blood having whiskey = [tex]\frac{100}{2.5}[/tex]×5.75 × 10⁴

Hence,

 Volume of whiskey = 23×10⁵ml

From the above conclusion we can say that , volume (in mL) of whiskey would raise his blood alcohol level to 8.0x10⁻⁴ g/mL is 23×10⁵ml

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