Respuesta :
Condensed electron configuration of:
Rb = 1s2 2s2p6 3s2p6d10 4s2p6 5s.
O = 1s2 2s2 2p4
Rb2O is a yellow solid. It plays important part in application of fuel cells.
Rb2O is called as Rubidium oxide.
Formal charge = FV-N-{B}÷{2}
FC = formal charge
V = number of valence electrons
N = number of nonbonding valence electrons
{B} = total number of electrons shared in bonds
Rubidium oxide is highly reactive towards water.
Rb is a Group 1 metal, and O (oxygen) is a Group 16 non metal. Metals and non metals combine to form ionic compounds where the metal will lose its valence electron(s) to form a metal cation while the non metal will gain electrons to form a non metal anion.
Since Rb has 1 valence electron that it loses to form a rubidium cation and achieve a noble gas configuration. The formation of the cation is denoted below:
Rb --> Rb⁺ + e⁻
Since Oxygen is in Group 16, it needs to gain 2 electrons to complete its octet and achieve a noble gas configuration. The formation of the anion is denoted below:
O + 2e- --> O₂⁻
When a metal cation and non metal anion combine to form an ionic compound, the sum of their charges must equal zero since the compound is neutral.
Thus the formula of their compound is: Rb₂O.
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