A small hole in the wing of a space shuttle requires a 20.7-cm² patch.
(b) If the patching material costs NASA $3.25/in², what is the cost of the patch?

Respuesta :

The answer is- The cost of the patch to cover the area of hole = $ 10.43.

Area: It is defined as the total space occupied by a flat (2-D) surface or shape of an object.

How can 1 [tex]cm^2[/tex] area be expressed as area in [tex]in^2[/tex]?

  • Inch and cm are the units for length while [tex]cm^2[/tex] and [tex]in^2[/tex] are the units for area of a surface.
  • The conversion factor is [tex]1\ cm = 0.394\ in\\[/tex].

and [tex]1\ cm^2 = 0.155\ in^2[/tex].

  • Now, area of patch = 20.7 [tex]cm^2[/tex].

This area of patch in square inch is calculated as-[tex]20.7\ cm^2 = (20.7 * 0.155) = 3.2085\ in^2[/tex]

  • Therefore, area of patch = 3.2085 [tex]in^2[/tex].
  • Next, the cost of 1 [tex]in^2[/tex] patch = $ 3.25. Thus, the cost of 3.2085 [tex]in^2[/tex] patch is-

[tex]Total\ cost =3.2085\ in^2 * ( {\$} 3.25/in^2) = {\$} 10.43.[/tex]

  • Hence, the cost of the patch to cover the area of hole = $ 10.43.

To learn more about area, visit:

https://brainly.com/question/20771646

#SPJ4