Longest wavelengths of light that can cleave the bonds in elemental nitrogen ,oxygen, fluorine is 1.27 x 10⁻⁷ m ,2.40 x 10⁻⁷ m,7.52 x 10⁻⁷ m
How do you calculate wavelength?
wavelength = NA x h C / bond energy
= 6.022 x 10²³ x 6.626 x 10⁻³⁴ x 3 x 10⁸ / (945 x 10³)
= 1.27 x 10⁻⁷ m
wavelength = NA x h C / bond energy
= 6.022 x 10²³ x 6.626 x 10⁻³⁴ x 3 x 10⁸ / (498 x 10³)
= 2.40 x 10⁻⁷ m
wavelength = NA x h C / bond energy
= 6.022 x 10²³ x 6.626 x 10⁻³⁴ x 3 x 10⁸ / (159 x 10³)
= 7.52 x 10⁻⁷ m
Where ,
NA is Avogadro's number
h is Planck's constant
C is speed of light.
So, the longest wavelengths of light that can cleave the bonds in elemental nitrogen ,oxygen, fluorine is 1.27 x 10⁻⁷ m ,2.40 x 10⁻⁷ m,7.52 x 10⁻⁷ m.
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