The reactant takes 1732.87 year to reach 12.5% of its original value when a decomposition reaction has a rate constant of 0.0012 yr⁻¹
Calculation ,
Formula used : Kt = ㏑a/a-x ( i )
where K is the rate constant = 0.0012 yr⁻¹ ( given )
t is the time = ?
a is the initial concentration of reactant = 100% ( known )
a- x is concentration of reactant at time t = 12.5 % ( given )
After putting the value of rate constant , initial concentration and concentration of reactant at time t in equation ( i ) we get the value of time .
0.0012 yr⁻¹ × t = ㏑100% / 12.5 % = ㏑8 = 2.303 ㏒ 8 = 2.303 × 0.9 = 2.07
t = 2.07 / 0.0012 yr⁻¹ = 1732.87 yr
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