Respuesta :
The half life of the reaction is 79.67 secs.
The time required for a reactant concentration to drop to half that of its initial concentration is known as the half-life of a reaction ([tex]t^{/12}[/tex]).
The half-life time is the length of time required for a quantity to fall to half of its starting value. Its value in half is 50%.
The half-life time is calculated using the following equation:
[At] = Concentration at time t; [Ai] = Initial Concentration; k = Rate Constant; t = Time; [At] = [Ai](e(-kt))
We are interested in learning how long it takes for anything to lose half its original value.
50 = 100 X [tex]e^{-8.7X 10^{-3}Xs^{-t} }[/tex]
50/100 = [tex]e^{-8.7X 10^{-3}Xs^{1-t} }[/tex]
ln(0.5) = [tex]8.7X10^{-3}Xs^{-t}[/tex]
t = ln(0.5)/ (-8,7)X10⁻³ = 79.67
So, the half life of the reaction is 79.67 secs.
Learn more about the Half-life of reaction with the help of the given link:
https://brainly.com/question/24710827
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