Respuesta :
The shape around each central atom in each molecule of H₂O₂ is bent (V-shape) and the bond angle is 101.9° in solid phase and 95.8° in liquid phase.
What is the explanation?
The hydrogen atom, the central atom of H₂O₂, has four single H-O bonds and one double H-O bond. There aren't any lone pairs. According to the VSEPR theory, the total number of bonds on the central atom (ignoring multiplicity and lone pairs) constitutes the steric number. H has four bonds altogether; there are no lone pairings. But we do have two solo pairings. This shows that the molecule has lost its tetrahedral shape and is bent at an angle of about. The angle is much lower than it would be in a bent (V-shaped) structure because there are lone pairs present that resist more strongly than the shared electrons.
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