Respuesta :
(a) Here, we are going to compare the the strength, length, and order of nitrogen-nitrogen bonds in hydrazine, diazene, and N₂.
Total valence electrons in N₂H₄ = 2 × 5 + 4×1 = 4e⁻
Thus, single N-N bond is present in hydrazine (N₂H₄) molecule. Therefore, the bond order is =1
Total valence electrons in N₂H₄ = 2× 5 + 2 ×1 = 12e⁻
Thus, one N=N bond is present in diazene (N₂H₂) molecule. Therefore, the bond order is =2
Total valence electrons in N₂ = 2 × 5 = 10e⁻
Thus, one N-N triple bond is present in nitrogen (N₂) molecule. Therefore, the bond order is =3.
Therefore, the order of bond order is given below:
N₂ (Bond order =3) > diazene (N₂H₂, bond order =2) > hydrazine (N₂H₄, bond order=1)
We know that, with the increasing bond order, the strength of the bond increases.
Therefore, the order of the strength of the bond is given below:
N₂ (Bond order =3) > diazene (N₂H₂, bond order =2) > hydrazine (N₂H₄, bond order=1)
What is Lewis structure explain with example?
A Lewis structure is based on the concept of the octet rule, in which atoms share electrons so that each atom has eight electrons in its outer shell. As an example, an oxygen atom has six electrons in its outer shell.
What is the Lewis structure rule?
The Lewis structure indicates that each Cl atom has three pairs of electrons that are not used in bonding (called lone pairs) and one shared pair of electrons (written between the atoms)
Learn more about Lewis structure :
brainly.com/question/1525249
#SPJ4
