Gaseous ammonia was introduced into a sealed container and heated to a certain temperature:2NH₃(g) ⇄ N₂(g) + 3H₂(g) At equilibrium, [NH₃] = 0.0225 M, [N₂] = 0.114 M, and [H₂] = 0.342 M. Calculate Kc for the reaction at this temperature.

Respuesta :

kc for reaction is :

K_c={9.01}K cK c= [N 2 ][H 2 ] 3[NH 3 ] 2= (0.0225) 2(0.114)(0.342) 3= 9.01

What is gaseous ammonia?

Ammonia can be produced by intestinal bacteria. The colourless gas known as ammonia has a potent aroma. Because ammonia is a common ingredient in window cleaners, household and industrial cleaners, and smelling salts, many people are familiar with this stench. Water can dissolve ammonia gas.

We must determine the Kc of the given reaction, which is presented below, in this problem. ​

2NH 3 (g)⇌N 2(g)+3H 2 (g)

Put our equilibrium constant's formulation in terms of concentration first.

KcKc= [reactant][product]= [N 2 ][H 2 ] 3[NH 3 ] 2

We can determine Kc by solving for each reaction component's concentration listed below.

[NH 3 ]=0.0225 M

[\{N}_2]=0.114\ \text{M}

[N 2]=0.114 M

[\{H}_2]=0.342\ \{M}[H2 ]=0.342 M

K_c= {(0.114)(0.342)^3}{(0.0225)^2}

Thus kc for reaction is :

K_c={9.01}K cK c= [N 2 ][H 2 ] 3[NH 3 ] 2= (0.0225) 2(0.114)(0.342) 3= 9.01

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