What is Chemical Equation?
A chemical equation is a symbolic representation of a chemical reaction in the form of symbols and formulae, with the reactant entities on the left and the product entities on the right, with a plus sign between the entities in both the reactants and the products and an arrow pointing towards the products and indicating the direction of the reaction. The absolute values of the stoichiometric numbers are represented by the coefficients adjacent to the symbols and formulas of things. Jean Beguin drew the first chemical equation in 1615.
Main Content
We will evaluate the mass of each chemical that remains after the process.
The balanced chemical equation is as follows:
Ca(NO[tex]_{3}[/tex])[tex]_{2}[/tex] (s) + 2NH[tex]_{4}[/tex]F(aq) [tex]\to[/tex] CaF[tex]_{2}[/tex](s) +2N[tex]_{2}[/tex]O(g) + 4H[tex]_{2}[/tex]O[tex](l)[/tex]
Determination of limiting reagent:
Calculate the moles of CaF[tex]_{2}[/tex] from the moles of Ca(NO[tex]_{3}[/tex])[tex]_{2}[/tex](s) if we consider NH[tex]_{4}[/tex]F(aq) the following as a limiting agent:
Given that,
The mass of Ca(NO[tex]_{3}[/tex])[tex]_{2}[/tex](s) =16.8 g
The molar mass of Ca(NO[tex]_{3}[/tex])[tex]_{2}[/tex](s) =164.10 g/mol
Therefore,
The moles of is Ca(NO[tex]_{3}[/tex])[tex]_{2}[/tex](s) is
=(16.8gCa(NO[tex]_{3}[/tex])[tex]_{2}[/tex](s)) [tex]\times[/tex] [tex]\frac{1.0molofCa(NO_{3})_{2} }{164.10gCa(NO_{3})_{2}} = 0.1023766 mol Ca(NO_{3})_{2}[/tex]
Thus,
The moles of from the moles of CaF[tex]_{2}[/tex] from the moles of Ca(NO[tex]_{3}[/tex])[tex]_{2}[/tex]
= 0.1023766 mol Ca(NO[tex]_{3}[/tex])[tex]_{2}[/tex] [tex]\times[/tex] [tex]\frac{1.0 mol ofCaF_{2} }{1.0 mol Ca(NO_{3})_{2} }[/tex]
= 0.1023766 mol = 0.102 mol CaF[tex]_{2}[/tex]
Therefore, 0.102 mol CaF[tex]_{2}[/tex] is formed from 0.1023766 mol Ca(NO[tex]_{3})_{2}[/tex]
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