Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound waves in phase at 688 hz. Take the speed of sound in air to be 344 m/s.

Respuesta :

With the sound waves in phase at 688 hz and the speed of sound in air to be 344 m/s we have a wavelength of 0.5 m

To solve this problem the formula and the procedure that we have to use is:

λ = v / f

Where:

  • f= frequency
  • v= wave speed
  • λ= wavelength

Information about the problem:

  • f= 688 Hz
  • v= 344 m/s
  • λ = ?
  • 1 Hz = s˄ -1

Using the wavelength formula and replacing values we get:

λ = v / f

λ = 344 m/s / 688 Hz

λ =0.5 m

What is frequency?

It is the quantity that measures the number of times or cycles in which a wave is repeated over time in seconds. Frequency is expressed in Hertz (Hz).

Learn more about frequency at: brainly.com/question/22674905

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