Respuesta :
0.012 mol of COâ‚‚ is the volume of COâ‚‚ is produced from 1.00 g of baking powder.
Balanced Equation:
Ca(H₂PO₄)₂(s) + 2NaHCO₃(s) → 2CO₂(g) + 2H₂O(g) + CaHPO₄(s) + Na₂HPO₄(s)
On 3.50 g of baking powerd:
mCa(Hâ‚‚POâ‚„)â‚‚ = 0.35*3.50 = 1.225 g
mNaHCO₃ = 0.31*3.50 = 1.085 g
The molar masses are: Ca = 40 g/mol; H = 1 g/mol; P = 31 g/mol; O = 16 g/mol; Na = 23 g/mol; C = 12 g/mol. So:
Ca(Hâ‚‚POâ‚„)â‚‚: 40 + 4x1 + 31 + 8x16 = 203 g/mol
NaHCO₃: 23 + 1 + 12 + 3x16 = 84 g/mol
The mass divided by the molar mass yields the number of moles, as in:
nCa(Hâ‚‚POâ‚„)â‚‚ = 1.225/203 = 0.006 mol
nNaHCO₃ = 1.085/84 = 0.0129 mol
Find the reactant that is limiting first. The stoichiometry for the Ca(Hâ‚‚POâ‚„)â‚‚ test is:
1 mol of Ca(H₂PO₄)₂ ---------- 2 mol of NaHCO₃
0.006 of Ca(Hâ‚‚POâ‚„)â‚‚ -------- x
By a simple direct three rule:
x = 0.012 mol
NaHCO₃ is therefore too much. After performing the stoichiometry calculus with the limiting reactant:
1 mol of Ca(Hâ‚‚POâ‚„)â‚‚ ------------- 2 mol of COâ‚‚
0.006 of Ca(Hâ‚‚POâ‚„)â‚‚ -------- x
By a simple direct three rule:
x = 0.012 mol of COâ‚‚
What is molar mass and how is it calculated?
The mass of every atom in a molecule, expressed in grams per mole, is known as the molar mass. We first obtain the atomic weights of the different elements in a periodic table in order to compute the molar mass of a molecule. Then, we multiply the total number of atoms by each one's atomic mass.
How is molar mass calculated and why is it important?
When converting a mass measurement to a substance amount, the molar mass ratio is utilized. The number of atoms, molecules, or ions that make up this quantity is used to express it. It is the proportion of an object's mass to the quantity of its constituent particles.
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