The molarity of B of two 25.0-mL aqueous solutions is 0.24 M.
Moles of Ca(OH)2 can be calculated.
Moles of Ca(OH)2 = 4 sphere of Ca + × 1 × 10 -³ moles of Ca+ / 1 sphere of Ca(+) × 1 mole of Ca(OH)2 / 1 moles of Ca+
= 4 × 10 -³moles of Ca (OH) 2
= 0.004 moles of Ca ( OH) 2
The moles of HCl can be calculated in the same way
Moles of HCl = 6 spheres of H(+) × 1 × 10 -³ moles of H(+) / 1 sphere of H(+) × 1 mole HCl / 1 mole of H+
= 6 × 10 - ³ moles of HCl
= 0.006 moles of HCl
Molarity is defined as the ratio of Number of moles of solute to the volume of solution (L)
Molarity of B ( HCl)
Molarity = Number of moles of solute / volume of solution (L)
= 0.24 M
Thus, we concluded that the molarity of B is 0.24 M.
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