blackdmnd2877 blackdmnd2877

23-08-2022
Chemistry

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For each reaction, predict the sign and find the value of(c) C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(g)

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tripatsingh039 tripatsingh039

27-08-2022

8.064 g of C6H12O6 will burn, producing 4.838 g of water.

6O2 + 6CO2 + 6H2O = C6H12O6

Molar Water and Glucose Masses

180.15588 g/mol of C6H12O6

Water at 18.0152 g/mol

Calculate the moles of glucose by dividing 8.064 g of glucose by its molar mass.

To calculate moles of water, multiply the 6mol H2O to 1mol 8C6H12O6 mol ratio from the balanced equation.

To get the mass of water, multiply by the molar mass of H2O.

1mol H2O = 4.838 g H2O = 8.064g C6H12O6 1mol C6H12O6 180.15588 g C6H12O6 6mol H2O 1mol C6H12O6 18.01528 g H2O

Learn more about Glucose here-

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