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Consider the oxidation of carbon monoxide:CO(g) + 1/2O₂(g) → CO₂(g) (a) Predict the signs of ΔS° and ΔH°. Explain.

Respuesta :

The signs of ΔS° and ΔH° will be negative.

Entropy (ΔS°)

Entropy is a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty. From classical thermodynamics, where it was originally recognized, through the microscopic description of nature in statistical physics, to the fundamentals of information theory, the phrase and concept are utilized in a variety of disciplines. It has numerous applications in physics and chemistry, biological systems and how they relate to life, cosmology, economics, sociology, weather science, and information systems, especially the exchange of information.

CO(g) + 1/2O₂(g) → CO₂(g)

ΔG°= {G°(CO2)- [G°(CO) + 1/2 G°(O2)]}

     = { -394.4 -[137.2  + 0]}

     = -257.2 KJ

Standard entropy change for the reaction is

ΔS°= 0.094 Kj /mol -k

ΔG°=ΔH° - TΔS°

ΔH° = -285.4 kJ

Therefore,

ΔS° and ΔH° both are negative.

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