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A 0.75-L bottle is cleaned, dried, and closed in a room where the air is 22°C and has 44% relative humidity (that is, the water vapor in the air is 0.44 of the equilibrium vapor pressure at 22°C). The bottle is then brought outside and stored at 0.0°C.
(b) Would liquid water condense at 10°C? (See Table 5.2, p. 220.)

Respuesta :

According to table equilibrium vapor pressure of water at 22oC is 198 Torr and at 0 o is 4.6 Torr.

At 22oC humidity is 44%% so water vapor is equal to:

44 %⋅19.8 Torr=8.712 Torr

44%⋅19.8Torr=8.712Torr

Convert 8.712 Torr to Pa:

8.712 Torr⋅133.32 Pa  /1 Torr=1161.48 Pa 8.712Torr⋅

=1161.48Pa

Now we can use the ideal gas law to find a number of moles of H2 O(g)

in the bottle.

22o C

pV=nRT

n=pV / RT

=1161.48 Pa⋅0.75⋅10^−3 m3     /  8.314 JK⋅mol⋅295 K

=3.55⋅10^−4mol

So number of moles of H2O that becomes liquid

=3.55⋅10^−4⋅2.03⋅10^−4 =1.52  ⋅10^−4 mol

Mass can be calculated from:

n-number of moles;

m-mass;

M-molar mass.

M(H2O)=2⋅1+16=18 gmol

m=n⋅M=1.52⋅10^−4 mol⋅18 gmol=2.74⋅10−3g=2.74 mg

b)

At 10o C vapor pressure is 9.2 Torr. Because vapor pressure is bigger than initial , there is no condensation.

to know more about relative humidity here

brainly.com/question/28302542

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