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Ammonium nitrate, a common fertilizer, was used by terrorists in the tragic explosion in Oklahoma City in 1995. How many liters of gas at 307°C and 1.00 atm are formed by the explosive decomposition of 15.0 kg of ammonium nitrate to nitrogen, oxygen, and water vapor?

Respuesta :

2NH4 NO3⟶ 2N2 +O2  +4H2O

T=307 °C= 580,15K

p=1 atm=101325Pa

its given the amount of mass of ammonium nitrate is 15kg

m(NH4 NO3 )=15kg=15000g

then the moles will =15000/ (80.043)/mol

Mr(NH4  NO3 )=80,04g/mol

n(NH4 NO3 ) = m/Mr= 187,05mol

total moles of products formed=7/2*n(NH4 NO3 )=655,92 mol

pV=nR*T

V=n∗R∗T /p

V=655,92∗8,314∗580,15  / 101325

V=31,22 m3

=31223,8L

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