Allotropes are different molecular forms of an element, such as dioxygen (O₂) and ozone (O₃). (b) Calculate the ratio of densities, d₀₃/d₀₂, and explain the significance of this number.

Respuesta :

The ratio of densities, d₀₃/d₀ is 3:2

We know that at STP all gas have the same volume that is [tex]$22.4 \mathrm{~L}$[/tex].

Dioxygen [tex]$1 \mathrm{mLe} \mathrm{O}_{2}=32 \mathrm{gm} / \mathrm{moL} .$[/tex]

Ozone 1 mole  [tex]$\mathrm{O}_{3}=48 \mathrm{gm} / \mathrm{mol}$[/tex].

[tex]$\begin{aligned} \therefore \text { density of } \mathrm{O}_{2} \text { at STP } &=\frac{\text { mass of } \mathrm{O}_{2}}{\text { volume }} \\ \text { or, } d_{\mathrm{O}_{2}} &=\frac{32 \mathrm{gm} / \mathrm{mol}_{\mathrm{o}}}{22.4 \mathrm{~L}} \end{aligned}$[/tex]

[tex]$\therefore$[/tex]The ratio of densities,

[tex]$\frac{d_{3}}{d o_{2}}=\frac{\frac{48 \mathrm{gm} / \mathrm{mol}}{22.4 \mathrm{~L}}}{\frac{32 \mathrm{gm} / \mathrm{mol}}{22.4 \mathrm{~L}}}$[/tex]

[tex]$\frac{d 0_{3}}{d 0_{2}}=\frac{3}{2}$[/tex]

do3: do2 = 3:2

Oxygen is found naturally as a molecule. two oxygen atoms strongly bind together with a covalent double bond to shape dioxygen or O2. Oxygen is normally observed as a molecule. it is referred to as dioxygen.

After hydrogen and helium, oxygen is the third most plentiful element in the universe and the most established element in the world. two atoms of the factors combine to generate dioxygen, an odourless and colourless diatomic gasoline with the formulation O2, at ordinary temperature and stress.

Learn more about dioxygen https://brainly.com/question/19905677

#SPJ4