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The voltage of the cell is 0.024 V and the cathode is half cell B
In a concentration cell, the cathode is the electrode with the more concentrated electrolyte solution. Half-cell B contains 0.87V of electrolyte, while half-cell A only has 0.13V. Half-cell B is the cathode.
To compute the voltage of the cell, the concentration of these half-cells must be used in the equation
Ecell= E0 cell-RT/nf ln(anode)/(cathode)
E0cell= E0(cell) -0.0591/n ln(anode)/cathode
E0(cell)=0 n=2, we get
Ecell=0-0.0591/2 ln 0.13/0.87
Ecell=0.024 V
What is a voltaic cell?
- A Voltaic Cell is a galvanic cell which is an electrochemical cell that uses spontaneous redox reactions to generate electricity.
- It consists of two separate half-cells.
- A half-cell is composed of an electrode containing a strip of metal M within a solution containing M^n+ ions in which M is any arbitrary metal.
To learn more about voltaic cells visit:
brainly.com/question/1370699
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