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One way of purifying gaseous H₂ is to pass it under high pressure through the holes of a metal’s crystal structure. Palladium, which adopts a cubic closest packed structure, absorbs more H₂ than any other element and is one of the metals used for this purpose. How the metal and H₂ interact is unclear, but it is estimated that the density of absorbed H₂ approaches that of liquid hydrogen (70.8 g/L). What volume (in L) of gaseous H₂ (at STP) can be packed into the spaces of 1 dm³ of palladium metal?

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khuranashilpa76

The volume (in L) of gaseous H₂ (at STP) that can be packed into the spaces of 1 dm³ of palladium is  786.688 L of H​​​​​​2 gas.

First, we have to calculate the number of moles of H​​​​​​2​​​​​ .

Given, density = 70.8 g/L

Since, density = mass/volume

                mass = density×volume

                          = 70.8g/L × 1 L

                         m = 70.8 g      

                   

We know, that no. of moles = given mass/molar mass

molar mass of H​​​​​​2 = 2×1.008 g/mol = 2.016 g/mol

Then, no. of moles of  H​​​​​​2   = 70.8 g/2.016gmol-1

                                                = 35.12 moles

                                           

at STP, 1 mol of any ideal gas will occupy volume = 22.4 L

Then,

35.12 mol of H​​​​​​2 will occupy =(22.4L/1 mol)×35.12 mol

                                               = 786.688 L

                                             

Therefore, at STP, 786.688 L of H​​​​​​2 gas can be packed into the spaces of 1 dm3 of palladium metal.

Learn more about palladium here:-https://brainly.com/question/14652727

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