901,310 C are required for electrolysis of molten NaCl.
To find the number of use this expression
Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Here,
Mass of Na = 215 g
Molar mass of Na = 23 g/mol
Now write the half reaction for electrolysis of molten NaCl
Na⁺ + 1e⁻ → Na(s)
From the above reaction we can say that 1 moles of electrons are transferred to deposit 1 mol of Na metal.
Now put the values in above expression
Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{215\ g}{23.0\ \text{g/mol}}[/tex]
= 9.34 mol
Charge carried by 1 mole e⁻ = 96500 C
Charge carried by 3.75 mole e⁻ = [tex]9.34\ \text{mole}\ e^- \times \frac{96500\ C}{1\ \text{mole}\ e^{-}}[/tex]
= 901,310 C
Thus from the above conclusion we can say that 901,310 C are required for electrolysis of molten NaCl.
Learn more about the Moles here: brainly.com/question/15356425
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