contestada

You are given the following three half-reactions:(1) Fe³⁺(aq) + e⁻ ⇄ Fe²⁺(aq) (2) Fe²⁺(aq) +2e⁻ ⇄ Fe(s) (3) Fe³⁺(aq) +3e⁻ ⇄ Fe(s) (b) Calculate ΔG° for (1) and (2) from their E°half-cell values.

Respuesta :

tanisharawat014

The Gibb's free energy of equation-1 and 2 respectively are 74305kj and -84920kj .

Given ,

1)  Fe3+(aq) +e =Fe2+

2) Fe2+(aq) +2e = Fe(s)

3) Fe3+(aq) +3e = Fe (s)

The E cell of the equation-1 is  0.77 volts .

Thus ,the Gibb's free energy of equation-1 is given by ,

[tex]delG^{0}=nFE^{0} cell = 1\times 96500\times 0.77 = 74305 kj[/tex]

Then the E cell of equation-2 is -0.44 volts .

Thus ,the Gibb's free energy of equation-2 is given by ,

[tex]delG^{0} =nFE^{0} cell = 2\times 96500\times (-0.44) =-84920 kj[/tex]

Hence the Gibb's free energy of equation-1 and 2 respectively are 74305kj and -84920kj .

Learn more about Gibb's energy here,

brainly.com/question/17310317

#SPJ4

Otras preguntas