Respuesta :
Balanced formation equation at standard conditions C (s, graphite) + 2Cl₂ (g) → CCl₄ (l) [ΔH° (C (s, graphite)) = 0 and ΔH° (Cl₂ (g)) = 0].
What is Chemical Reaction ?
A chemical reaction is a process in which chemical bonds between atoms to break and reorganize, to form a other new substances.
The chemical reaction for CCl₄ is
C (s, graphite) + Cl₂ (g) → CCl₄ (l)
Reactant Side Product Side
C = 1 C = 1
Cl = 2 Cl = 4
In the reactant side there are 2 Cl atoms and in the product side there are 4 Cl atoms. So multiply by 2 in the reactant side.
C (s, graphite) + 2Cl₂ (g) → CCl₄ (l)
Reactant Side Product Side
C = 1 C = 1
Cl = 4 Cl = 4
Now, the above equation is balanced.
Now, write the balanced formation equation at standard conditions
C (s, graphite) + 2Cl₂ (g) → CCl₄ (l) [ΔH° (C (s, graphite)) = 0 and ΔH° (Cl₂ (g)) = 0]
Thus from the above conclusion we can say that Balanced formation equation at standard conditions C (s, graphite) + 2Cl₂ (g) → CCl₄ (l) [ΔH° (C (s, graphite)) = 0 and ΔH° (Cl₂ (g)) = 0]
Learn more about the Chemical equation here: https://brainly.com/question/11231920
#SPJ4
