Respuesta :
Balanced formation equation at standard conditions 3Ca (s) + 2P (s, white) + 4O₂ → Ca₃(PO₄)₂ [ΔH° (Ca (s)) = 0 and ΔH° (P (s, white) = 0 and ΔH° (O₂ (g)) = 0]
What is Chemical Reaction ?
A chemical reaction is a process in which chemical bonds between atoms to break and reorganize, to form a other new substances.
The chemical reaction for Ca₃(PO₄)₂ is
Ca (s) + P (s, white) + O₂ → Ca₃(PO₄)₂
Reactant Side Product Side
Ca = 1 Ca = 3
P = 1 P = 2
O = 2 O = 8
In the reactant side there are 1 Ca atoms and in the product side 3P atoms. So multiply by 3 in the reactant side to balance Ca atoms.
3Ca (s) + P (s, white) + O₂ → Ca₃(PO₄)₂
Reactant Side Product Side
Ca = 3 Ca = 3
P = 1 P = 2
O = 2 O = 8
In the reactant side there are 1 P atoms and in the product side 2P atoms. So multiply by 2 in the reactant side to balance P atoms.
3Ca (s) + 2P (s, white) + O₂ → Ca₃(PO₄)₂
Reactant Side Product Side
Ca = 3 Ca = 3
P = 2 P = 2
O = 2 O = 8
In the reactant side there are 2 O atoms and in the product side 8 O atoms. So multiply by 4 in the reactant side to balance O atoms.
3Ca (s) + 2P (s, white) + 4O₂ → Ca₃(PO₄)₂
Reactant Side Product Side
Ca = 3 Ca = 3
P = 2 P = 2
O = 8 O = 8
Now, write the balanced formation equation at standard conditions
3Ca (s) + 2P (s, white) + 4O₂ → Ca₃(PO₄)₂ [ΔH° (Ca (s)) = 0 and ΔH° (P (s, white) = 0 and ΔH° (O₂ (g)) = 0]
Thus from the above conclusion we can say that Balanced formation equation at standard conditions 3Ca (s) + 2P (s, white) + 4O₂ → Ca₃(PO₄)₂ [ΔH° (Ca (s)) = 0 and ΔH° (P (s, white) = 0 and ΔH° (O₂ (g)) = 0]
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