Diluting sulfuric acid with water is highly exothermic:
H₂SO₄(l) → H₂SO₄(aq) + heat
(a) Use Appendix B to find ΔH°rxn for diluting 1.00 mol of H₂SO₄(l) (d = 1.83 g/mL) to 1 L of 1.00 M H₂SO₄(aq) (d = 1.060 g/mL).

Question

23-08-2022
Chemistry

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Diluting sulfuric acid with water is highly exothermic:
H₂SO₄(l) → H₂SO₄(aq) + heat
(a) Use Appendix B to find ΔH°rxn for diluting 1.00 mol of H₂SO₄(l) (d = 1.83 g/mL) to 1 L of 1.00 M H₂SO₄(aq) (d = 1.060 g/mL).

Respuesta :

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tripatsingh039 tripatsingh039 · Answer 1 · 2022-08-26T14:39:52+02:00

ΔH°rxn for diluting 1.00 mol of H₂SO₄(l) is -93.5 KJ/mol.

The quantity of heat absorbed (+ΔHvalue) or emitted (-ΔHvalue) as a result of a chemical reaction is known as the Standard Enthalpy of Reaction (ΔH°rxn). The difference between the total molar enthalpies of the reactant and product, calculated for the substances in their standard states, is the standard enthalpy of reaction for a chemical reaction.

A negative H indicates that heat is transferred from a system to its surroundings, whereas a positive H indicates that heat is transferred from the surroundings into the system. The enthalpy of reaction (ΔH°rxn) for a chemical reaction is the difference in enthalpy between the products and reactants; Hrxn is measured in kilojoules per mole.

ΔH°rxn = ΔH°f (products)- ΔH°f (reactants)

ΔH°f (reactants) = - 813.9 KJ/mol.

ΔH°f (products) = - 907.51

ΔH°rxn = - 907.51 -(- 813.9)

ΔH°rxn = -93.5 KJ/mol.

To know more about ΔH°rxn refer to: https://brainly.com/question/13981527

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Diluting sulfuric acid with water is highly exothermic: H₂SO₄(l) → H₂SO₄(aq) + heat (a) Use Appendix B to find ΔH°rxn for diluting 1.00 mol of H₂SO₄(l) (d = 1.83 g/mL) to 1 L of 1.00 M H₂SO₄(aq) (d = 1.060 g/mL).

Respuesta :

Otras preguntas

Diluting sulfuric acid with water is highly exothermic:
H₂SO₄(l) → H₂SO₄(aq) + heat
(a) Use Appendix B to find ΔH°rxn for diluting 1.00 mol of H₂SO₄(l) (d = 1.83 g/mL) to 1 L of 1.00 M H₂SO₄(aq) (d = 1.060 g/mL).