The mass percent of iron ores in Fe2O₃, Fe₃O₄, and FeS₂ is 70%, 72.3% and 46.6% respectively.
The ratio of the mass of the solute contained in a solution to the mass of the solution as a whole is known as the mass percent.
Mass of Fe2O3 ore = 2 x 55.8 g + 3 x 16 g = 159.6 g
Hence; mass percent of iron = 2 x 55.8 g/159.6g x 100 = 70%
For Fe3O4 ore:Mass of Fe3O4 ore = 3 x 55.8 g + 4 × 16 g = 231.4 g
Hence; mass percent of iron = 3x55.8g /231.4g x100= 72.3%
For FeS2 oreMass of FeS2 ore= 1 x 55.8 g + 2 x 32 g = 119.8 g
Hence; mass percent of iron = 55.88 x100 /119.8g =46.6%
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