Respuesta :
The order of the energy of the photons of given wave will be
= Ultraviolet waves > infrared waves > microwaves
[tex]E = hv[/tex]
where,
E = energy of photon
[tex]v[/tex] = frequency of the radiation
h = Planck's constant = [tex]6.63[/tex]×[tex]10[/tex]⁻³⁴ [tex]J s[/tex]
We have :
(a) Frequency of infrared waves = [tex]v[/tex]₁ = [tex]6.5[/tex]×[tex]10[/tex]¹³[tex]J s[/tex]
(b) Frequency of microwaves= [tex]v[/tex]₂ = [tex]9.8[/tex]×[tex]10[/tex]¹¹ [tex]J s[/tex]
(c) Frequency of ultraviolet waves = [tex]v[/tex]₃ = [tex]8[/tex]×[tex]10[/tex]¹⁵[tex]J s[/tex]
So, the decreasing order of the frequencies of the waves will be :
[tex]v[/tex]₃ [tex]>[/tex][tex]v[/tex]₁[tex]> v[/tex]₂
As we can see from the formula that energy is directly proportional to the frequency of the wave.
[tex]E[/tex]∝[tex]v[/tex]
So, the order of the energy of the photons of given wave will be same as their order of frequencies:
[tex]E[/tex]₃> [tex]E[/tex]₁ >[tex]E[/tex]₂
= Ultraviolet waves > infrared waves > microwaves
Also the complete question is :
Rank the following photons in terms of decreasing energy:
(a) IR (v = 6.5 x 10¹³ s⁻¹)
(b) microwave (v = 9.8 x 10¹¹ s⁻¹)
(c) UV (v = 8.0 x 10¹⁵ s⁻¹)
To learn more about microwaves visit the link:
https://brainly.com/question/19811153
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