The mass percentage of the solution is 137.2% .
The mass percent is described as the grams of solute per grams of solution, multiplied by 100 to get Percentage. The mass percent formula is expressed as solving for the molar mass also for the mass of each element in 1mole of the compound.
Mass percentage→mass of solute×100/mass of solution .
We have given here the moles of isopropanol are 0.35 mol and moles of water are 0.85 ,molar mass of isopropanol is 60g/ mol and the molar mass of water is 18g/ mol .
Mass of isopropanol=35×60→2.10g
mass of H20 is 85×18→15.30g
Mass percent →2.10×100/15.30
mass percentage→137.2%
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