An octahedral complex with three different ligands (A, B, and C) can have formulas with three different ratios of the ligands:[MA₄BC]ⁿ⁺, such as [Co(NH₃)₄(H₂O)Cl]²⁺[MA₃B₂C]ⁿ⁺, such as [Cr(H₂O)₃Br₂Cl][MA₂B₂C2]ⁿ⁺, such as [Cr(NH₃)₂(H₂O)₂Br₂]⁺For each example, give the name, state the type(s) of isomerism present, and draw all isomers.

Respuesta :

The octahedral complexes form when six ligands approach to the metal so, metal in an octahedral complex requires six hybrid orbitals for the interaction with ligands. Hybrid orbitals are formed by the mixing of s, p and d orbitals.

How is the octahedral complex formed?

According to CFT, an octahedral metal complex forms because of the electrostatic interaction of a positively charged metal ion with six negatively charged ligands or with the negative ends of dipoles associated with the six ligands. In addition, the ligands interact with one other electrostatically.

Why octahedral complex is more stable than tetrahedral?

Generally speaking, octahedral complexes will be favored over tetrahedral ones because: It is more (energetically) favorable to form six bonds rather than four. The CFSE is usually greater for octahedral than tetrahedral complexes.

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