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In order to comply with the requirement that energy be conserved, Einstein showed in the photoelectric effect that the energy of a photon (hv) absorbed by a metal is the sum of the work function (Φ), the minimum energy needed to dislodge an electron from the metal’s surface, and the kinetic energy (Eκ) of the electron: hv = Φ + Eκ. When light of wavelength 358.1 nm falls on the surface of potassium metal, the speed (u) of the dislodged electron is 6.403105 m/s.
(a) What is Ek(1/2 mu²) of the dislodged electron?

Respuesta :

Based on these observations, Einstein hypothesised that light acted as a stream of photons with an energy of E=hnuE=hv, E, , h, nu.

What is the photoelectric effect?

The photoelectric effect occurs when light shines on a metal and causes electrons to be expelled from the metal's surface. This process is also known as photoemission, and the electrons released from the metal are known as photoelectrons. In terms of behaviour and attributes, photoelectrons are identical to other electrons. The photo- prefix merely indicates that electrons have been expelled from a metal surface by incoming light.

To explain the photoelectric effect, 19th-century physicists proposed that the incoming light wave's fluctuating electric field heated the electrons and caused them to vibrate, finally releasing them off the metal surface.

Learn more about photoelectric effect refer:

https://brainly.com/question/21320305

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