What is the minimum mass of ethylene glycol (C₂H₆O₂) that must be dissolved in 14.5 kg of water to prevent the solution from freezing at -12.0°F? (Assume ideal behavior.)

Respuesta :

7250 gms is the minimum mass of ethylene glycol required to prevent the solution from freezing.

A liquid's freezing point is the temperature at which it turns into a solid. Similar to the melting point, the freezing point typically rises with increasing pressure.

Given;

We are aware that a colligative property of depression in freezing point depends on molality as.

In order to have a freezing point of -12.0°F means we need a depression in freezing point to be −24.4°c

we know that depression in freezing point is a colligative property which depends on molality as

depression in freezing point  = Kf X molality

Kf = 1.86 °C/m

molality = moles of solute / mass of solvent in Kg

15 = 1.86 °C/m X molality

molality = 8.065

molality = moles of glycerol / mass of water in Kg

moles of glycerol = 8.065 X 14.5

moles = 116.9425

moles = mass / molar mass

mass = moles X molar mass = 116.9425 X 62 = 7250 grams

7250 gms is the minimum mass of ethylene glycol required to prevent the solution from freezing.

Learn more about the Freezing point with the help of the given link:

brainly.com/question/3121416

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