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In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles: α,β⁻,β⁻,α,α,α,α,β⁻,β⁻ and α. Write a balanced equation for each step.

Respuesta :

The reactions in which the nucleus participates are called nuclear reactions. Nuclear reactions are characterized by the emission of powerful rays like α,βandγ rays. Due to this emission, new nuclides will be generated.

The parent nuclide given is thorium-232.

If an alpha particle decays then, its atomic number decreases by two units and the mass number decreases by four units.

For a beta particle decay, the atomic number of the parent nuclide increases by one and there is no change in its mass number.

The symbol of an alpha particle is shown below:

₂He⁴

The symbol of the beta particle is shown below:

₋₁e⁰

The balanced chemical equations for the consequent decay of α,β⁻,β⁻,α,α,α,α,β⁻,β⁻ α paticles from the parent nuclide are shown below:

₉₀Th²³² → ₂He⁴ +₈₈Ra²²⁸

₈₈Ra²²⁸ → ₋₁e⁰ +₈₉Ac²²⁸

₈₉Ac²²⁸ → ₋₁e⁰ + ₉₀Th²²⁸

₉₀Th²²⁸ → ₂He⁴+ ₈₈Ra²²⁸

₈₈Ra²²⁴ →  ₂He⁴+ ₈₆Rn²²⁰

To learn more about decay processes from given link

https://brainly.com/question/8788860

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