We Know That,
The formula of distance between two points is
P(x1, y1) and Q(x2, y2) is given by:
d (P, Q) =
[tex] \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
Here,
Given that -
1 mile east and 3 miles north for one point and the other point is 7 miles east and 11 miles north
Therefore,
The two points are H(1,3) and E(7,11)
[tex] = \sqrt{ {(7 - 1)}^{2} + {(11 - 3)}^{2} } [/tex]
[tex] = \sqrt{ {6}^{2} + {8}^{2} } [/tex]
= 10 miles.
Hence
the shortest distance the helicopter can travel to get to the enemy patrol is 10 miles.
We Know That,
Distance between two points is the length of the line segment that connects the two given points. Distance between two points in coordinate geometry can be calculated by finding the length of the line segment joining the given coordinates.
The distance between any two points is the length of the line segment joining the points. There is only one line passing through two points. So, the distance between two points can be calculated by finding the length of this line segment connecting the two points.
Learn more about distance between 2 points at : https://brainly.com/question/15958176?referrer=searchResults
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