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Answer:
6 additional gigabytes. The price is $79.2 per month.
Step-by-step explanation:
To solve this problem, let's create a system of linear equations and solve it.
1. Create the equation ofCompany A.
This equation will give us the price that a service has based on the amount of gigabytes that a requested plan has.
[tex]C_A(g)=9.80g+20.40[/tex]; where g is the amount of gigabytes that a requested plan has
2. Create the equation of Company B.
Using the same as for Company A, Companie B's equation is the following:
[tex]C_B(g)=10.10g+18.60[/tex]
3. Write both equations in terms of "x" and "y".
[tex]y=9.80x+20.40\\\\y=10.10x+18.60[/tex]
4. Equal the right side of both equations.
[tex]9.80x+20.40=10.10x+18.60[/tex]
5. Substract 20.40 from both sides.
[tex]9.80x+20.40-20.40=10.10x+18.60-20.40\\ \\9.80x=10.10x-1.8[/tex]
6. Substract 10.10x from both sides.
[tex]9.80x-10.10x=10.10x-10.10x-1.8\\ \\-0.3x=-1.8[/tex]
7. Divide both sides by -0.3.
[tex]\frac{-0.3x}{-0.3} =\frac{-1.8}{-0.3} \\ \\x=6[/tex]
8. Conclude.
Taking into account that we formed a system of equations with equations that give the price of a services based on the number of additional, the number of additional gigabytes that make the price be the same is the solution of x for said system, which is x= 6.
9. (Extra) What would be the price?
To find out this information, just substitute the value of x= 6 into any of the equations and calculate the price:
[tex]C_B(6)=10.10(6)+18.60=79.2[/tex]
Hence, the price is $79.2 per month.
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Answer:
6 additional gigabytes
Step-by-step explanation:
Given information:
- Company A charges $20.40 monthly for up to 3 gigabytes of data and $9.80 per additional gigabyte.
- Company B charges $18.60 monthly for up to 3 gigabytes of data and $10.10 per additional gigabyte.
Define the variables:
- Let x = number of additional gigabytes of data.
- Let y = total charge (in dollars).
Create two equations with the given information and the defined variables:
[tex]\begin{cases}\textsf{Company A:} \quad y=20.40+9.80x\\\textsf{Company B:} \quad y=18.60+10.10x\end{cases}[/tex]
To find the number of additional gigabytes for which the two companies would charge the same amount, substitute the second equation into the first equation and solve for x:
[tex]\begin{aligned}& \textsf{Substitute}: & 18.60+10.10x & = 20.40+9.80x\\\\& \textsf{Subtract 18.60 from both sides}: & 10.10x & = 1.80+9.80x\\\\& \textsf{Subtract 9.80}x \textsf{ from both sides}: & 0.30x & = 1.80\\\\& \textsf{Divide both sides by 0.30}: & x & = 6\end{aligned}[/tex]
Therefore, the two companies will charge the same amount for 6 additional gigabytes.
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