The mass of NHâ‚„ClOâ‚„ needed to react for every kilogram of Al is 4.351 Kg
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
3Al + 3NH₄ClO₄ -> Al₂O₃ + AlCl₃ + 3NO + 6H₂O
Molar mass of Al = 27 g/mol
Mass of Al from the balanced equation = 3 × 27 = 81 g = 81 / 1000 = 0.081 Kg
Molar mass of NHâ‚„ClOâ‚„ = 117.5 g/mol
Mass of NH₄ClO₄ from the balanced equation = 3 × 117.5 = 352.5 g = 352.5 / 1000 = 0.3525 Kg
SUMMARY
From the balanced equation above,
0.081 Kg of Al reacted with 0.3525 Kg of NHâ‚„ClOâ‚„
From the balanced equation above,
0.081 Kg of Al reacted with 0.3525 Kg of NHâ‚„ClOâ‚„
Therefore,
1 Kg of Al will react with = (1 × 0.3525) / 0.081 = 4.351 Kg of NH₄ClO₄
Thus, 4.351 Kg of NHâ‚„ClOâ‚„ is needed for the reaction.
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