The original volume of the solution is 29 ml.
Given,
After the addition of an acid, a solution has a volume of 90 milliliters.
The volume of the solution is 3 milliliters greater than three times the volume of the solution before acid was added.
We need to find what was the original volume of the solution.
Find the volume of the solution after the acid is added.
V(acid) = 90 ml
Find the volume of the solution before the acid was added.
= V( no acid)
We have,
The volume of the solution is 3 milliliters greater than three times the volume of the solution before acid was added.
V ( acid ) = 3 V ( no acid ) + 3 ml
90 ml = 3 V ( no acid ) + 3 ml
90 ml - 3 ml = 3 V ( no acid )
87 ml = 3 V ( no acid )
Dividing by 3 on both sides.
87/3 ml = 3/3 V ( no acid )
29 ml = V ( no acid )
V ( no acid ) = 29 ml
Thus the original volume of the solution is 29 ml.
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