Answer:
d ≈ 5.4 units
Step-by-step explanation:
using the distance formula given
with (x₁, y₁ ) = (- 1, 2 ) and (x₂, y₂ ) = (4, 0 )
d = [tex]\sqrt{(4-(-1))^2+(0-2)^2}[/tex]
= [tex]\sqrt{(4+1)^2+(-2)^2}[/tex]
= [tex]\sqrt{5^2+4}[/tex]
= [tex]\sqrt{25+4}[/tex]
= [tex]\sqrt{29}[/tex]
≈ 5.4 ( to the nearest tenth )
