The required number of additional passengers of the same average weight that can carry by elevator is 7.
Given that,
An elevator can accommodate a maximum of 2000 pounds,
Four passengers on the elevator have an average weight of 180 ib each,
In mathematics, it deals with numbers of operations according to the statements.
how many additional passengers of the same average weight can the elevator carry before the maximum weight capacity is exceeded is to be determined.
Here,
Let the total number of passengers be x whose average weight is 180 lbs
Now,
An elevator can accommodate a maximum of 2000 pounds, which Implies
2000 = 180x
x = 2000 / 180
x ≈ 11
Number of additional pair = 11 - 4 = 7
Thus, the required number of additional passengers of the same average weight that can carry by elevator is 7.
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